A girl has as many brothers as sisters, but each brother has only half as many brothers as sisters. How many brothers and sisters are there in the family? (no googling)
A girl has as many brothers as sisters, but each brother has only half as many brothers as sisters. How many brothers and sisters are there in the family? (no googling)
3 each?
Shouldn't the girl already know how many brothers and/or sisters are in her family?
Shouldn't the girl already know how many brothers and/or sisters are in her family?
s = number of sisters
b = number of brothers
s - 1 = b
2(b - 1) = s
2b - 2 = s
2b - 2 - 1 = b
2b - 3 = b
b - 3 = 0
b = 3
Three brothers and three sisters.
Waitaminute that contradicts my earlier math statements.
Edit: oh yeah (@)The_Daethalus is correct its supposed to be 3 brothers and 4 sisters
Me dumb
s = number of sisters
b = number of brothers
s - 1 = b
2(b - 1) = s
2b - 2 = s
2b - 2 - 1 = b
2b - 3 = b
b - 3 = 0
b = 3
Three brothers and three sisters.
Waitaminute that contradicts my earlier math statements.
Edit: oh yeah (@)The_Daethalus is correct its supposed to be 3 brothers and 4 sisters
Me dumb
4 sisters and 3 brothers.
4 sisters and 3 brothers.
3 brothers 4 sisters
Is this right?
3 brothers 4 sisters
Is this right?
@InkyDarkBird said in #4:
s = number of sisters
b = number of brothers
s - 1 = b
2(b - 1) = s
2b - 2 = s
2b - 2 - 1 = b
2b - 3 = b
b - 3 = 0
b = 3
Three brothers and three sisters.
Waitaminute that contradicts my earlier math statements.
Edit: oh yeah (@)The_Daethalus is correct its supposed to be 3 brothers and 4 sisters
Me dumb
You were right, you just need to plug b into the first equation and solve for s.
@InkyDarkBird said in #4:
> s = number of sisters
> b = number of brothers
> s - 1 = b
> 2(b - 1) = s
> 2b - 2 = s
> 2b - 2 - 1 = b
> 2b - 3 = b
> b - 3 = 0
> b = 3
>
> Three brothers and three sisters.
> Waitaminute that contradicts my earlier math statements.
> Edit: oh yeah (@)The_Daethalus is correct its supposed to be 3 brothers and 4 sisters
> Me dumb
You were right, you just need to plug b into the first equation and solve for s.
@InkyDarkBird said in #4:
s = number of sisters
b = number of brothers
s - 1 = b
2(b - 1) = s
2b - 2 = s
2b - 2 - 1 = b
2b - 3 = b
b - 3 = 0
b = 3
Three brothers and three sisters.
Waitaminute that contradicts my earlier math statements.
Edit: oh yeah (@)The_Daethalus is correct its supposed to be 3 brothers and 4 sisters
Me dumb
@The_Daethalus said in #5:
4 sisters and 3 brothers.
@ChessKK888 said in #6:
3 brothers 4 sisters
Is this right?
correct
@InkyDarkBird said in #4:
> s = number of sisters
> b = number of brothers
> s - 1 = b
> 2(b - 1) = s
> 2b - 2 = s
> 2b - 2 - 1 = b
> 2b - 3 = b
> b - 3 = 0
> b = 3
>
> Three brothers and three sisters.
> Waitaminute that contradicts my earlier math statements.
> Edit: oh yeah (@)The_Daethalus is correct its supposed to be 3 brothers and 4 sisters
> Me dumb
@The_Daethalus said in #5:
> 4 sisters and 3 brothers.
@ChessKK888 said in #6:
> 3 brothers 4 sisters
> Is this right?
correct
@GloweyySquidd said in #8:
correct
Yes! I knew it
@GloweyySquidd said in #8:
> correct
Yes! I knew it