1 + 4 = 5
2 + 5 = 12
3 + 6 = 21
4 + 7 =
5 + 8 =
6 + 9 =
7 + 10 =
8 + 11 = ?
Soluce :
1 + (4 * 1) = 5
2 + (5 * 2) = 12
3 + (6 * 3) = 21
4 + (7 * 4) = 32
5 + (8 * 5) = 45
6 + (9 * 6) = 60
7 + (10 * 7) = 77
8 + (11 * 8) = 96
How to develop this suite ?
Un = n + (4 * n) =
this is how i solved it...
1 + 4 = (4x1+1)=5
2 + 5 =(5x2+2)=12
3 + 6 = (6x3 +3)=21
8 + 11 = (11x8+8)=96
96 le résultat de la photo
I think it is 40 because you add the numbers you have and then the previous sum. Ex 1 + 4 = 5, so next was 2 + 5 which is 7 + 5 of the previous making it 12 which works for the next equation as well.
@Sebi_PRO said in #51:
1 + 4 = 5
2 + 5 = 12
3 + 6 = 21
4 + 7 =
5 + 8 =
6 + 9 =
7 + 10 =
8 + 11 = ?
Soluce :
1 + (4 * 1) = 5
2 + (5 * 2) = 12
3 + (6 * 3) = 21
4 + (7 * 4) = 32
5 + (8 * 5) = 45
6 + (9 * 6) = 60
7 + (10 * 7) = 77
8 + (11 * 8) = 96
How to develop this suite ?
Un = n + (3 + n) * n) =
Little correction
There are 2 answers to the question, 96 and 40. While many people say that 96 is the only answer, 40 works perfectly well
Came here to see if I was the only one who had got it. No surprise, I wasn't :)
Also great article.