Given two disjoint sets {a, b} and {c, d}. Take their union—how many elements are in the resulting set? If there are 5, what is the fifth element?
@KhrivenilSSP said [^](/forum/redirect/post/XyBjtnNE)
> Given two disjoint sets {a, b} and {c, d}. Take their union—how many elements are in the resulting set? If there are 5, what is the fifth element?
There is no fifth element!
@Anonymous_IIII said [^](/forum/redirect/post/Q6tMdu3J)
> > Given two disjoint sets {a, b} and {c, d}. Take their union—how many elements are in the resulting set? If there are 5, what is the fifth element?
>
> There is no fifth element!
Of course there are only 4.
@KhrivenilSSP said [^](/forum/redirect/post/bUJ2PWbu)
> > > Given two disjoint sets {a, b} and {c, d}. Take their union—how many elements are in the resulting set? If there are 5, what is the fifth element?
> >
> > There is no fifth element!
>
> Of course there are only 4.
Then wtf u meant??
@KhrivenilSSP said [^](/forum/redirect/post/XyBjtnNE)
> Given two disjoint sets {a, b} and {c, d}. Take their union—how many elements are in the resulting set? If there are 5, what is the fifth element?
Guys, why would you question a fifth element? Every set contains Ø or nothing. Therefore, the union of the sets is {a, b, c, d, Ø}
@Anonymous_IIII said [^](/forum/redirect/post/Kczz02a4)
> > > > Given two disjoint sets {a, b} and {c, d}. Take their union—how many elements are in the resulting set? If there are 5, what is the fifth element?
> > >
> > > There is no fifth element!
> >
> > Of course there are only 4.
>
> Then wtf u meant??
Maybe you should read the previous pages before commenting.
@O_olo_O said [^](/forum/redirect/post/mlNoSzqe)
> > Given two disjoint sets {a, b} and {c, d}. Take their union—how many elements are in the resulting set? If there are 5, what is the fifth element?
>
> Guys, why would you question a fifth element? Every set contains Ø or nothing. Therefore, the union of the sets is {a, b, c, d, Ø}
Then it should be {Ø, {Ø}, {Ø, {Ø}}, {Ø, {Ø}, {Ø, {Ø}}}} since everything can be used as nil. {Ø, {Ø}, {Ø, {Ø}}, {Ø, {Ø}, {Ø, {Ø}}}} is equivalent to {a, b, c, d}, while your "a b c d nil" should be {Ø, {Ø}, {Ø, {Ø}}, {Ø, {Ø}, {Ø, {Ø}}}, {Ø, {Ø}, {Ø, {Ø}}, {Ø, {Ø}, {Ø, {Ø}}}}}.
@Anonymous_IIII said [^](/forum/redirect/post/Kczz02a4)
> > > > Given two disjoint sets {a, b} and {c, d}. Take their union—how many elements are in the resulting set? If there are 5, what is the fifth element?
> > >
> > > There is no fifth element!
> >
> > Of course there are only 4.
>
> Then wtf u meant??
I meant that 2+2=4, not 5.
@HuaTianXiangQi said [^](/forum/redirect/post/nuTJMcnM)
> > > Given two disjoint sets {a, b} and {c, d}. Take their union—how many elements are in the resulting set? If there are 5, what is the fifth element?
> >
> > Guys, why would you question a fifth element? Every set contains Ø or nothing. Therefore, the union of the sets is {a, b, c, d, Ø}
>
> Then it should be {Ø, {Ø}, {Ø, {Ø}}, {Ø, {Ø}, {Ø, {Ø}}}} since ...
Yes, infinite elements, neither four, nor five, not even 10. Infinite. But I don't think that's the answer high school maths teachers are looking for.